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The vertical matchsticks on the scale all have the same weight. To balance the unbalanced scale you need to MOVE 1 matchstick. Where would you place it?
In the original puzzle:
Left of balancing point: (3x1) + (1x1) + (1x1) + (1x1) = 6 units
Right of balancing point: (3x1) + (4x1) = 7 units
From the above we can see we need to move a matchstick right of the balancing point. This is done by placing the matchstick as shown in the solution.
Left of balancing point: (3x1) + (1x1) + (1x1) + (1x1) = 6 units
Right of balancing point: (3x1) + (4x1) = 7 units
From the above we can see we need to move a matchstick right of the balancing point. This is done by placing the matchstick as shown in the solution.
move the matchstick at 3 on the right side to 4
ReplyDeleteIt can also be:
ReplyDeleteL.H.S:
Moving 1 matchstick from 1 to 2
[(Matchstick*Distance)] (2*1)+(1*2)+(3*1) = 7 units
Absolutely, thanks!
DeleteMove 1 stick from the LEFT side, 1 step to the left ((6+1) = 7), either:
ReplyDelete- the one at 3 moved to 4
- one of the 1s moved to 2
OR
Move 1 stick from the RIGHT side, 1 step to the left (6 = (7-1)), either:
- the one at 3 moved to 2
- the one at 4 moved to 3